(3n+3)=(2n-1)

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Solution for (3n+3)=(2n-1) equation: 



(3n+3)=(2n-1)

We move all terms to the left:

(3n+3)-((2n-1))=0

We get rid of parentheses

3n-((2n-1))+3=0



We calculate terms in parentheses: -((2n-1)), so:

(2n-1)

We get rid of parentheses

2n-1

Back to the equation:

-(2n-1)



We get rid of parentheses

3n-2n+1+3=0

We add all the numbers together, and all the variables

n+4=0

We move all terms containing n to the left, all other terms to the right

n=-4

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