(3n+5)/2=4+(4n+2)/4

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Solution for (3n+5)/2=4+(4n+2)/4 equation: 



(3n+5)/2=4+(4n+2)/4

We move all terms to the left:

(3n+5)/2-(4+(4n+2)/4)=0

We calculate fractions


3n/()+(-(4+(4n+2)*2)/()=0



We calculate terms in parentheses: +(-(4+(4n+2)*2)/(), so:

-(4+(4n+2)*2)/(

We multiply all the terms by the denominator


-(4+(4n+2)*2)



We calculate terms in parentheses: -(4+(4n+2)*2), so:

4+(4n+2)*2

determiningTheFunctionDomain
(4n+2)*2+4

We multiply parentheses

8n+4+4

We add all the numbers together, and all the variables

8n+8

Back to the equation:

-(8n+8)



We get rid of parentheses

-8n-8

Back to the equation:

+(-8n-8)



We get rid of parentheses

3n/()-8n-8=0

We multiply all the terms by the denominator


3n-8n*()-8*()=0

We add all the numbers together, and all the variables

3n-8n*()=0

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