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(3n+6)(6n-3)=0
We multiply parentheses ..
(+18n^2-9n+36n-18)=0
We get rid of parentheses
18n^2-9n+36n-18=0
We add all the numbers together, and all the variables
18n^2+27n-18=0
a = 18; b = 27; c = -18;
Δ = b2-4ac
Δ = 272-4·18·(-18)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-45}{2*18}=\frac{-72}{36} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+45}{2*18}=\frac{18}{36} =1/2 $
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