(3n-1)+(4-1)=12(13-3)

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Solution for (3n-1)+(4-1)=12(13-3) equation: 



(3n-1)+(4-1)=12(13-3)

We move all terms to the left:

(3n-1)+(4-1)-(12(13-3))=0

We add all the numbers together, and all the variables

(3n-1)+3-(1210)=0

We add all the numbers together, and all the variables

(3n-1)-1207=0

We get rid of parentheses

3n-1-1207=0

We add all the numbers together, and all the variables

3n-1208=0

We move all terms containing n to the left, all other terms to the right

3n=1208

n=1208/3

n=402+2/3

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