(3n-1)+(4-1)=12(13-3)

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Solution for (3n-1)+(4-1)=12(13-3) equation:



(3n-1)+(4-1)=12(13-3)
We move all terms to the left:
(3n-1)+(4-1)-(12(13-3))=0
We add all the numbers together, and all the variables
(3n-1)+3-(1210)=0
We add all the numbers together, and all the variables
(3n-1)-1207=0
We get rid of parentheses
3n-1-1207=0
We add all the numbers together, and all the variables
3n-1208=0
We move all terms containing n to the left, all other terms to the right
3n=1208
n=1208/3
n=402+2/3

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