(3n-1)=2(n+5)

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Solution for (3n-1)=2(n+5) equation: 



(3n-1)=2(n+5)

We move all terms to the left:

(3n-1)-(2(n+5))=0

We get rid of parentheses

3n-(2(n+5))-1=0



We calculate terms in parentheses: -(2(n+5)), so:

2(n+5)

We multiply parentheses

2n+10

Back to the equation:

-(2n+10)



We get rid of parentheses

3n-2n-10-1=0

We add all the numbers together, and all the variables

n-11=0

We move all terms containing n to the left, all other terms to the right

n=11

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