(3n-5)-4(2n+4)=-36

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Solution for (3n-5)-4(2n+4)=-36 equation: 



(3n-5)-4(2n+4)=-36

We move all terms to the left:

(3n-5)-4(2n+4)-(-36)=0

We add all the numbers together, and all the variables

(3n-5)-4(2n+4)+36=0

We multiply parentheses

(3n-5)-8n-16+36=0

We get rid of parentheses

3n-8n-5-16+36=0

We add all the numbers together, and all the variables

-5n+15=0

We move all terms containing n to the left, all other terms to the right

-5n=-15

n=-15/-5

n=+3

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