(3n-6)+(4n+12)+(2n+8)=140

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Solution for (3n-6)+(4n+12)+(2n+8)=140 equation:


Simplifying
(3n + -6) + (4n + 12) + (2n + 8) = 140

Reorder the terms:
(-6 + 3n) + (4n + 12) + (2n + 8) = 140

Remove parenthesis around (-6 + 3n)
-6 + 3n + (4n + 12) + (2n + 8) = 140

Reorder the terms:
-6 + 3n + (12 + 4n) + (2n + 8) = 140

Remove parenthesis around (12 + 4n)
-6 + 3n + 12 + 4n + (2n + 8) = 140

Reorder the terms:
-6 + 3n + 12 + 4n + (8 + 2n) = 140

Remove parenthesis around (8 + 2n)
-6 + 3n + 12 + 4n + 8 + 2n = 140

Reorder the terms:
-6 + 12 + 8 + 3n + 4n + 2n = 140

Combine like terms: -6 + 12 = 6
6 + 8 + 3n + 4n + 2n = 140

Combine like terms: 6 + 8 = 14
14 + 3n + 4n + 2n = 140

Combine like terms: 3n + 4n = 7n
14 + 7n + 2n = 140

Combine like terms: 7n + 2n = 9n
14 + 9n = 140

Solving
14 + 9n = 140

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 9n = 140 + -14

Combine like terms: 14 + -14 = 0
0 + 9n = 140 + -14
9n = 140 + -14

Combine like terms: 140 + -14 = 126
9n = 126

Divide each side by '9'.
n = 14

Simplifying
n = 14

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