(3n-64)1/2=(n/3)1/2

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Solution for (3n-64)1/2=(n/3)1/2 equation: 


n in (-oo:+oo)

((3*n-64)^1)/2 = ((n/3)^1)/2 // - ((n/3)^1)/2

((3*n-64)^1)/2-(((n/3)^1)/2) = 0

(3*n-64)/2+(-1/6)*n = 0

(3*n-64)/2-n/6 = 0

(6*(3*n-64))/(2*6)+(2*(-n))/(2*6) = 0

6*(3*n-64)+2*(-n) = 0

16*n-384 = 0

(16*n-384)/(2*6) = 0

(16*n-384)/(2*6) = 0 // * 2*6

16*n-384 = 0

16*n-384 = 0 // + 384

16*n = 384 // : 16

n = 384/16

n = 24

n = 24

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