(3n=2)(n+3)

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Solution for (3n=2)(n+3) equation: 



(3n=2)(n+3)

We move all terms to the left:

(3n-(2)(n+3))=0



We calculate terms in parentheses: +(3n-2(n+3)), so:

3n-2(n+3)

We multiply parentheses

3n-2n-6

We add all the numbers together, and all the variables

n-6

Back to the equation:

+(n-6)



We get rid of parentheses

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6

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