(3p-q)/7=(5p-2q)/10=

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Solution for (3p-q)/7=(5p-2q)/10= equation: 


1;2;1;3;0;0

1;2;1;3;0;0

1;3;1;2;0;0

(3*p-q)/7 = 0

X^2-16 = 0

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