(3p/2)-(1/3)=(2/p)

Solution for (3p/2)-(1/3)=(2/p) equation:

(3p/2)-(1/3)=(2/p)

We move all terms to the left:

(3p/2)-(1/3)-((2/p))=0


Domain of the equation: p))!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+3p/2)-((+2/p))-(+1/3)=0

We get rid of parentheses

3p/2-((+2/p))-1/3=0

We calculate fractions


(-2p^2)/6p+9p^2/6p+()/6p=0

We multiply all the terms by the denominator


(-2p^2)+9p^2+()=0

We add all the numbers together, and all the variables

9p^2+(-2p^2)=0

We get rid of parentheses

9p^2-2p^2=0

We add all the numbers together, and all the variables

7p^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{14}=0$