(3q+1)(3q-1)=

Solution for (3q+1)(3q-1)= equation:

Simplifying
(3q + 1)(3q + -1) = 0

Reorder the terms:
(1 + 3q)(3q + -1) = 0

Reorder the terms:
(1 + 3q)(-1 + 3q) = 0

Multiply (1 + 3q) * (-1 + 3q)
(1(-1 + 3q) + 3q * (-1 + 3q)) = 0
((-1 * 1 + 3q * 1) + 3q * (-1 + 3q)) = 0
((-1 + 3q) + 3q * (-1 + 3q)) = 0
(-1 + 3q + (-1 * 3q + 3q * 3q)) = 0
(-1 + 3q + (-3q + 9q2)) = 0

Combine like terms: 3q + -3q = 0
(-1 + 0 + 9q2) = 0
(-1 + 9q2) = 0

Solving
-1 + 9q2 = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 9q2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 9q2 = 0 + 1
9q2 = 0 + 1

Combine like terms: 0 + 1 = 1
9q2 = 1

Divide each side by '9'.
q2 = 0.1111111111

Simplifying
q2 = 0.1111111111

Take the square root of each side:
q = {-0.333333333, 0.333333333}