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(3q+6)-5q=8-(2q-1)
We move all terms to the left:
(3q+6)-5q-(8-(2q-1))=0
We add all the numbers together, and all the variables
-5q+(3q+6)-(8-(2q-1))=0
We get rid of parentheses
-5q+3q-(8-(2q-1))+6=0
We calculate terms in parentheses: -(8-(2q-1)), so:We add all the numbers together, and all the variables
8-(2q-1)
determiningTheFunctionDomain -(2q-1)+8
We get rid of parentheses
-2q+1+8
We add all the numbers together, and all the variables
-2q+9
Back to the equation:
-(-2q+9)
-2q-(-2q+9)+6=0
We get rid of parentheses
-2q+2q-9+6=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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