(3q-40)=(2q+11)

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Solution for (3q-40)=(2q+11) equation: 



(3q-40)=(2q+11)

We move all terms to the left:

(3q-40)-((2q+11))=0

We get rid of parentheses

3q-((2q+11))-40=0



We calculate terms in parentheses: -((2q+11)), so:

(2q+11)

We get rid of parentheses

2q+11

Back to the equation:

-(2q+11)



We get rid of parentheses

3q-2q-11-40=0

We add all the numbers together, and all the variables

q-51=0

We move all terms containing q to the left, all other terms to the right

q=51

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