(3q2+4q-2)/q

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Solution for (3q2+4q-2)/q equation:


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

(3*q^2+4*q-2)/q = 0

3*q^2+4*q-2 = 0

3*q^2+4*q-2 = 0

DELTA = 4^2-(-2*3*4)

DELTA = 40

DELTA > 0

q = (40^(1/2)-4)/(2*3) or q = (-40^(1/2)-4)/(2*3)

q = (2*10^(1/2)-4)/6 or q = (-2*10^(1/2)-4)/6

(q-((-2*10^(1/2)-4)/6))*(q-((2*10^(1/2)-4)/6)) = 0

((q-((-2*10^(1/2)-4)/6))*(q-((2*10^(1/2)-4)/6)))/q = 0

( q-((-2*10^(1/2)-4)/6) )

q-((-2*10^(1/2)-4)/6) = 0 // + (-2*10^(1/2)-4)/6

q = (-2*10^(1/2)-4)/6

( q-((2*10^(1/2)-4)/6) )

q-((2*10^(1/2)-4)/6) = 0 // + (2*10^(1/2)-4)/6

q = (2*10^(1/2)-4)/6

q in { (-2*10^(1/2)-4)/6, (2*10^(1/2)-4)/6 }

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