(3r+1)+(r+2)=65

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Solution for (3r+1)+(r+2)=65 equation:


Simplifying
(3r + 1) + (r + 2) = 65

Reorder the terms:
(1 + 3r) + (r + 2) = 65

Remove parenthesis around (1 + 3r)
1 + 3r + (r + 2) = 65

Reorder the terms:
1 + 3r + (2 + r) = 65

Remove parenthesis around (2 + r)
1 + 3r + 2 + r = 65

Reorder the terms:
1 + 2 + 3r + r = 65

Combine like terms: 1 + 2 = 3
3 + 3r + r = 65

Combine like terms: 3r + r = 4r
3 + 4r = 65

Solving
3 + 4r = 65

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4r = 65 + -3

Combine like terms: 3 + -3 = 0
0 + 4r = 65 + -3
4r = 65 + -3

Combine like terms: 65 + -3 = 62
4r = 62

Divide each side by '4'.
r = 15.5

Simplifying
r = 15.5

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