(3r+1)2+(r+2)=65

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Solution for (3r+1)2+(r+2)=65 equation: 



(3r+1)2+(r+2)=65

We move all terms to the left:

(3r+1)2+(r+2)-(65)=0

We multiply parentheses

6r+(r+2)+2-65=0

We get rid of parentheses

6r+r+2+2-65=0

We add all the numbers together, and all the variables

7r-61=0

We move all terms containing r to the left, all other terms to the right

7r=61

r=61/7

r=8+5/7

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