(3r+9)/6=(2r-8)/2

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Solution for (3r+9)/6=(2r-8)/2 equation: 



(3r+9)/6=(2r-8)/2

We move all terms to the left:

(3r+9)/6-((2r-8)/2)=0

We calculate fractions


3r/()+(-((2r-8)*6)/()=0



We calculate terms in parentheses: +(-((2r-8)*6)/(), so:

-((2r-8)*6)/(

We multiply all the terms by the denominator


-((2r-8)*6)



We calculate terms in parentheses: -((2r-8)*6), so:

(2r-8)*6

We multiply parentheses

12r-48

Back to the equation:

-(12r-48)



We get rid of parentheses

-12r+48

Back to the equation:

+(-12r+48)



We get rid of parentheses

3r/()-12r+48=0

We multiply all the terms by the denominator


3r-12r*()+48*()=0

We add all the numbers together, and all the variables

3r-12r*()=0

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