(3r-2)/5=(5+2r)/8

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Solution for (3r-2)/5=(5+2r)/8 equation: 



(3r-2)/5=(5+2r)/8

We move all terms to the left:

(3r-2)/5-((5+2r)/8)=0

We add all the numbers together, and all the variables

(3r-2)/5-((2r+5)/8)=0

We calculate fractions


3r/()+(-((2r+5)*5)/()=0



We calculate terms in parentheses: +(-((2r+5)*5)/(), so:

-((2r+5)*5)/(

We multiply all the terms by the denominator


-((2r+5)*5)



We calculate terms in parentheses: -((2r+5)*5), so:

(2r+5)*5

We multiply parentheses

10r+25

Back to the equation:

-(10r+25)



We get rid of parentheses

-10r-25

Back to the equation:

+(-10r-25)



We get rid of parentheses

3r/()-10r-25=0

We multiply all the terms by the denominator


3r-10r*()-25*()=0

We add all the numbers together, and all the variables

3r-10r*()=0

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