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(3s+2)=(12-2s)
We move all terms to the left:
(3s+2)-((12-2s))=0
We add all the numbers together, and all the variables
(3s+2)-((-2s+12))=0
We get rid of parentheses
3s-((-2s+12))+2=0
We calculate terms in parentheses: -((-2s+12)), so:We get rid of parentheses
(-2s+12)
We get rid of parentheses
-2s+12
Back to the equation:
-(-2s+12)
3s+2s-12+2=0
We add all the numbers together, and all the variables
5s-10=0
We move all terms containing s to the left, all other terms to the right
5s=10
s=10/5
s=2
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