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(3s+7)(7s-6)=0
We multiply parentheses ..
(+21s^2-18s+49s-42)=0
We get rid of parentheses
21s^2-18s+49s-42=0
We add all the numbers together, and all the variables
21s^2+31s-42=0
a = 21; b = 31; c = -42;
Δ = b2-4ac
Δ = 312-4·21·(-42)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-67}{2*21}=\frac{-98}{42} =-2+1/3 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+67}{2*21}=\frac{36}{42} =6/7 $
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