(3t)/(3t+4)+(2)/(5)=(1)/(3t-4)

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Solution for (3t)/(3t+4)+(2)/(5)=(1)/(3t-4) equation: 



(3t)/(3t+4)+(2)/(5)=(1)/(3t-4)

We move all terms to the left:

(3t)/(3t+4)+(2)/(5)-((1)/(3t-4))=0



Domain of the equation: (3t+4)!=0

We move all terms containing t to the left, all other terms to the right

3t!=-4

t!=-4/3

t!=-1+1/3

t∈R





Domain of the equation: (3t-4))!=0

t∈R



We calculate fractions


(-15t^2)/((3t+4)*(3t-4))*5)+(-(1*(3t+4)*5)/((3t+4)*(3t-4))*5)+(2*(3t+4)*(3t-4)))/((3t+4)*(3t-4))*5)=0

We can not solve this equation

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