(3t+1)/4=(1/3)y

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Solution for (3t+1)/4=(1/3)y equation:


x in (-oo:+oo)

(3*t+1)/4 = (1/3)*y // - (1/3)*y

(3*t+1)/4-((1/3)*y) = 0

(3*t+1)/4+(-1/3)*y = 0

(3*t+1)/4-y/3 = 0

(3*(3*t+1))/(3*4)+(4*(-y))/(3*4) = 0

3*(3*t+1)+4*(-y) = 0

9*t-4*y+3 = 0

(9*t-4*y+3)/(3*4) = 0

(9*t-4*y+3)/(3*4) = 0 // * 3*4

9*t-4*y+3 = 0

x belongs to the empty set

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