(3t+1)/4=(3/4)t-5

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Solution for (3t+1)/4=(3/4)t-5 equation: 


t in (-oo:+oo)

(3*t+1)/4 = (3/4)*t-5 // - (3/4)*t-5

(3*t+1)/4-((3/4)*t)+5 = 0

(3*t+1)/4+(-3/4)*t+5 = 0

(3*t+1)/4+(-3*t)/4+5 = 0

(3*t+1)/4+(-3*t)/4+(4*5)/4 = 0

3*t-3*t+4*5+1 = 0

1+20 = 0

21 = 0

21/4 = 0

21/4 = 0 // * 4

21 = 0

t belongs to the empty set

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