(3t+2)+(2t+5)+(t)+(5t+1)=202

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Solution for (3t+2)+(2t+5)+(t)+(5t+1)=202 equation: 



(3t+2)+(2t+5)+(t)+(5t+1)=202

We move all terms to the left:

(3t+2)+(2t+5)+(t)+(5t+1)-(202)=0

We add all the numbers together, and all the variables

t+(3t+2)+(2t+5)+(5t+1)-202=0

We get rid of parentheses

t+3t+2t+5t+2+5+1-202=0

We add all the numbers together, and all the variables

11t-194=0

We move all terms containing t to the left, all other terms to the right

11t=194

t=194/11

t=17+7/11

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