(3t-2)(7t-4)=-

Solution for (3t-2)(7t-4)=- equation:

(3t-2)(7t-4)=-

We move all terms to the left:

(3t-2)(7t-4)-(-)=0

We add all the numbers together, and all the variables

(3t-2)(7t-4)-0=0

We add all the numbers together, and all the variables

(3t-2)(7t-4)=0

We multiply parentheses ..

(+21t^2-12t-14t+8)=0

We get rid of parentheses

21t^2-12t-14t+8=0

We add all the numbers together, and all the variables

21t^2-26t+8=0

a = 21; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·21·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*21}=\frac{24}{42}
=4/7
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*21}=\frac{28}{42}
=2/3
$