(3t-2)(t-10)=0

Solution for (3t-2)(t-10)=0 equation:

(3t-2)(t-10)=0

We multiply parentheses ..

(+3t^2-30t-2t+20)=0

We get rid of parentheses

3t^2-30t-2t+20=0

We add all the numbers together, and all the variables

3t^2-32t+20=0

a = 3; b = -32; c = +20;
Δ = b2-4ac
Δ = -322-4·3·20
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-28}{2*3}=\frac{4}{6}
=2/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+28}{2*3}=\frac{60}{6}
=10
$