(3t-2)-(2t+3)=t-5

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Solution for (3t-2)-(2t+3)=t-5 equation: 



(3t-2)-(2t+3)=t-5

We move all terms to the left:

(3t-2)-(2t+3)-(t-5)=0

We get rid of parentheses

3t-2t-t-2-3+5=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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