(3t-2)/4=(2t+3)/3=3/3-t

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Solution for (3t-2)/4=(2t+3)/3=3/3-t equation: 



(3t-2)/4=(2t+3)/3=3/3-t

We move all terms to the left:

(3t-2)/4-((2t+3)/3)=0

We calculate fractions


3t/()+(-((2t+3)*4)/()=0



We calculate terms in parentheses: +(-((2t+3)*4)/(), so:

-((2t+3)*4)/(

We multiply all the terms by the denominator


-((2t+3)*4)



We calculate terms in parentheses: -((2t+3)*4), so:

(2t+3)*4

We multiply parentheses

8t+12

Back to the equation:

-(8t+12)



We get rid of parentheses

-8t-12

Back to the equation:

+(-8t-12)



We get rid of parentheses

3t/()-8t-12=0

We multiply all the terms by the denominator


3t-8t*()-12*()=0

We add all the numbers together, and all the variables

3t-8t*()=0

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