(3t-4)2-13(3t-4)+40=0

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Solution for (3t-4)2-13(3t-4)+40=0 equation:



(3t-4)2-13(3t-4)+40=0
We multiply parentheses
6t-39t-8+52+40=0
We add all the numbers together, and all the variables
-33t+84=0
We move all terms containing t to the left, all other terms to the right
-33t=-84
t=-84/-33
t=2+6/11

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