(3t-5)=(t+2)

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Solution for (3t-5)=(t+2) equation: 



(3t-5)=(t+2)

We move all terms to the left:

(3t-5)-((t+2))=0

We get rid of parentheses

3t-((t+2))-5=0



We calculate terms in parentheses: -((t+2)), so:

(t+2)

We get rid of parentheses

t+2

Back to the equation:

-(t+2)



We get rid of parentheses

3t-t-2-5=0

We add all the numbers together, and all the variables

2t-7=0

We move all terms containing t to the left, all other terms to the right

2t=7

t=7/2

t=3+1/2

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