(3t2+2t)+(t2-t)=4t2-t

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Solution for (3t2+2t)+(t2-t)=4t2-t equation: 



(3t^2+2t)+(t2-t)=4t^2-t

We move all terms to the left:

(3t^2+2t)+(t2-t)-(4t^2-t)=0

We add all the numbers together, and all the variables

(+t^2-1t)+(3t^2+2t)-(4t^2-t)=0

We get rid of parentheses

t^2+3t^2-4t^2-1t+2t+t=0

We add all the numbers together, and all the variables

2t=0

t=0/2

t=0

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