(3u-1)(2+u)=0

Solution for (3u-1)(2+u)=0 equation:

(3u-1)(2+u)=0

We add all the numbers together, and all the variables

(3u-1)(u+2)=0

We multiply parentheses ..

(+3u^2+6u-1u-2)=0

We get rid of parentheses

3u^2+6u-1u-2=0

We add all the numbers together, and all the variables

3u^2+5u-2=0

a = 3; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·3·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*3}=\frac{-12}{6}
=-2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*3}=\frac{2}{6}
=1/3
$