(3u-2)*5=(5u-1)*3-7

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Solution for (3u-2)*5=(5u-1)*3-7 equation: 


Simplifying
(3u + -2) * 5 = (5u + -1) * 3 + -7

Reorder the terms:
(-2 + 3u) * 5 = (5u + -1) * 3 + -7

Reorder the terms for easier multiplication:
5(-2 + 3u) = (5u + -1) * 3 + -7
(-2 * 5 + 3u * 5) = (5u + -1) * 3 + -7
(-10 + 15u) = (5u + -1) * 3 + -7

Reorder the terms:
-10 + 15u = (-1 + 5u) * 3 + -7

Reorder the terms for easier multiplication:
-10 + 15u = 3(-1 + 5u) + -7
-10 + 15u = (-1 * 3 + 5u * 3) + -7
-10 + 15u = (-3 + 15u) + -7

Reorder the terms:
-10 + 15u = -3 + -7 + 15u

Combine like terms: -3 + -7 = -10
-10 + 15u = -10 + 15u

Add '10' to each side of the equation.
-10 + 10 + 15u = -10 + 10 + 15u

Combine like terms: -10 + 10 = 0
0 + 15u = -10 + 10 + 15u
15u = -10 + 10 + 15u

Combine like terms: -10 + 10 = 0
15u = 0 + 15u
15u = 15u

Add '-15u' to each side of the equation.
15u + -15u = 15u + -15u

Combine like terms: 15u + -15u = 0
0 = 15u + -15u

Combine like terms: 15u + -15u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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