(3v+2)(9-v)=0

Solution for (3v+2)(9-v)=0 equation:

(3v+2)(9-v)=0

We add all the numbers together, and all the variables

(3v+2)(-1v+9)=0

We multiply parentheses ..

(-3v^2+27v-2v+18)=0

We get rid of parentheses

-3v^2+27v-2v+18=0

We add all the numbers together, and all the variables

-3v^2+25v+18=0

a = -3; b = 25; c = +18;
Δ = b2-4ac
Δ = 252-4·(-3)·18
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-29}{2*-3}=\frac{-54}{-6}
=+9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+29}{2*-3}=\frac{4}{-6}
=-2/3
$