(3v+2)-(v+1)=v+(2*v+3)

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Solution for (3v+2)-(v+1)=v+(2*v+3) equation: 



(3v+2)-(v+1)=v+(2v+3)

We move all terms to the left:

(3v+2)-(v+1)-(v+(2v+3))=0

We get rid of parentheses

3v-v-(v+(2v+3))+2-1=0



We calculate terms in parentheses: -(v+(2v+3)), so:

v+(2v+3)

We get rid of parentheses

v+2v+3

We add all the numbers together, and all the variables

3v+3

Back to the equation:

-(3v+3)



We add all the numbers together, and all the variables

2v-(3v+3)+1=0

We get rid of parentheses

2v-3v-3+1=0

We add all the numbers together, and all the variables

-1v-2=0

We move all terms containing v to the left, all other terms to the right

-v=2

v=2/-1

v=-2

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