(3v+2)-(v+1)=v+2(2v+3)

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Solution for (3v+2)-(v+1)=v+2(2v+3) equation: 



(3v+2)-(v+1)=v+2(2v+3)

We move all terms to the left:

(3v+2)-(v+1)-(v+2(2v+3))=0

We get rid of parentheses

3v-v-(v+2(2v+3))+2-1=0



We calculate terms in parentheses: -(v+2(2v+3)), so:

v+2(2v+3)

We multiply parentheses

v+4v+6

We add all the numbers together, and all the variables

5v+6

Back to the equation:

-(5v+6)



We add all the numbers together, and all the variables

2v-(5v+6)+1=0

We get rid of parentheses

2v-5v-6+1=0

We add all the numbers together, and all the variables

-3v-5=0

We move all terms containing v to the left, all other terms to the right

-3v=5

v=5/-3

v=-1+2/3

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