(3v+4)(2-v)=0

Solution for (3v+4)(2-v)=0 equation:

(3v+4)(2-v)=0

We add all the numbers together, and all the variables

(3v+4)(-1v+2)=0

We multiply parentheses ..

(-3v^2+6v-4v+8)=0

We get rid of parentheses

-3v^2+6v-4v+8=0

We add all the numbers together, and all the variables

-3v^2+2v+8=0

a = -3; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*-3}=\frac{-12}{-6}
=+2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*-3}=\frac{8}{-6}
=-1+1/3
$