(3v+5)(2v+7)=0

Solution for (3v+5)(2v+7)=0 equation:

(3v+5)(2v+7)=0

We multiply parentheses ..

(+6v^2+21v+10v+35)=0

We get rid of parentheses

6v^2+21v+10v+35=0

We add all the numbers together, and all the variables

6v^2+31v+35=0

a = 6; b = 31; c = +35;
Δ = b2-4ac
Δ = 312-4·6·35
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-11}{2*6}=\frac{-42}{12}
=-3+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+11}{2*6}=\frac{-20}{12}
=-1+2/3
$