(3v-2)(3v-7)=0

Solution for (3v-2)(3v-7)=0 equation:

(3v-2)(3v-7)=0

We multiply parentheses ..

(+9v^2-21v-6v+14)=0

We get rid of parentheses

9v^2-21v-6v+14=0

We add all the numbers together, and all the variables

9v^2-27v+14=0

a = 9; b = -27; c = +14;
Δ = b2-4ac
Δ = -272-4·9·14
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-15}{2*9}=\frac{12}{18}
=2/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+15}{2*9}=\frac{42}{18}
=2+1/3
$