(3v-7)(3v-7)=0

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Solution for (3v-7)(3v-7)=0 equation: 



(3v-7)(3v-7)=0

We multiply parentheses ..

(+9v^2-21v-21v+49)=0

We get rid of parentheses

9v^2-21v-21v+49=0

We add all the numbers together, and all the variables

9v^2-42v+49=0

a = 9; b = -42; c = +49;
Δ = b2-4ac
Δ = -422-4·9·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{42}{18}=2+1/3$

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