(3v-8)(3v+4)=0

Solution for (3v-8)(3v+4)=0 equation:

(3v-8)(3v+4)=0

We multiply parentheses ..

(+9v^2+12v-24v-32)=0

We get rid of parentheses

9v^2+12v-24v-32=0

We add all the numbers together, and all the variables

9v^2-12v-32=0

a = 9; b = -12; c = -32;
Δ = b2-4ac
Δ = -122-4·9·(-32)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*9}=\frac{-24}{18}
=-1+1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*9}=\frac{48}{18}
=2+2/3
$