(3w+1)(2w-3)=(3w-1)(2w+1)

Solution for (3w+1)(2w-3)=(3w-1)(2w+1) equation:

(3w+1)(2w-3)=(3w-1)(2w+1)

We move all terms to the left:

(3w+1)(2w-3)-((3w-1)(2w+1))=0

We multiply parentheses ..

(+6w^2-9w+2w-3)-((3w-1)(2w+1))=0


We calculate terms in parentheses: -((3w-1)(2w+1)), so:

(3w-1)(2w+1)

We multiply parentheses ..

(+6w^2+3w-2w-1)

We get rid of parentheses

6w^2+3w-2w-1

We add all the numbers together, and all the variables

6w^2+w-1

Back to the equation:

-(6w^2+w-1)


We get rid of parentheses

6w^2-6w^2-9w+2w-w-3+1=0

We add all the numbers together, and all the variables

-8w-2=0

We move all terms containing w to the left, all other terms to the right

-8w=2

w=2/-8

w=-1/4