(3w+2)(4+w)=0

Solution for (3w+2)(4+w)=0 equation:

(3w+2)(4+w)=0

We add all the numbers together, and all the variables

(3w+2)(w+4)=0

We multiply parentheses ..

(+3w^2+12w+2w+8)=0

We get rid of parentheses

3w^2+12w+2w+8=0

We add all the numbers together, and all the variables

3w^2+14w+8=0

a = 3; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·3·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*3}=\frac{-24}{6}
=-4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*3}=\frac{-4}{6}
=-2/3
$