(3w+4)(2+w)=0

Solution for (3w+4)(2+w)=0 equation:

(3w+4)(2+w)=0

We add all the numbers together, and all the variables

(3w+4)(w+2)=0

We multiply parentheses ..

(+3w^2+6w+4w+8)=0

We get rid of parentheses

3w^2+6w+4w+8=0

We add all the numbers together, and all the variables

3w^2+10w+8=0

a = 3; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·3·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*3}=\frac{-12}{6}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*3}=\frac{-8}{6}
=-1+1/3
$