(3w+6)(4w+8)=0

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Solution for (3w+6)(4w+8)=0 equation: 



(3w+6)(4w+8)=0

We multiply parentheses ..

(+12w^2+24w+24w+48)=0

We get rid of parentheses

12w^2+24w+24w+48=0

We add all the numbers together, and all the variables

12w^2+48w+48=0

a = 12; b = 48; c = +48;
Δ = b2-4ac
Δ = 482-4·12·48
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-48}{24}=-2$

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