(3w-10w)(w-3)=2

Solution for (3w-10w)(w-3)=2 equation:

(3w-10w)(w-3)=2

We move all terms to the left:

(3w-10w)(w-3)-(2)=0

We add all the numbers together, and all the variables

(-7w)(w-3)-2=0

We multiply parentheses ..

(-7w^2+21w)-2=0

We get rid of parentheses

-7w^2+21w-2=0

a = -7; b = 21; c = -2;
Δ = b2-4ac
Δ = 212-4·(-7)·(-2)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{385}}{2*-7}=\frac{-21-\sqrt{385}}{-14}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{385}}{2*-7}=\frac{-21+\sqrt{385}}{-14}
$