(3w-2)(8+w)=0

Solution for (3w-2)(8+w)=0 equation:

(3w-2)(8+w)=0

We add all the numbers together, and all the variables

(3w-2)(w+8)=0

We multiply parentheses ..

(+3w^2+24w-2w-16)=0

We get rid of parentheses

3w^2+24w-2w-16=0

We add all the numbers together, and all the variables

3w^2+22w-16=0

a = 3; b = 22; c = -16;
Δ = b2-4ac
Δ = 222-4·3·(-16)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*3}=\frac{-48}{6}
=-8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*3}=\frac{4}{6}
=2/3
$