(3w-7)(3+w)=0

Solution for (3w-7)(3+w)=0 equation:

(3w-7)(3+w)=0

We add all the numbers together, and all the variables

(3w-7)(w+3)=0

We multiply parentheses ..

(+3w^2+9w-7w-21)=0

We get rid of parentheses

3w^2+9w-7w-21=0

We add all the numbers together, and all the variables

3w^2+2w-21=0

a = 3; b = 2; c = -21;
Δ = b2-4ac
Δ = 22-4·3·(-21)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-16}{2*3}=\frac{-18}{6}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+16}{2*3}=\frac{14}{6}
=2+1/3
$