(3x)(-2x)=-30

Solution for (3x)(-2x)=-30 equation:

(3x)(-2x)=-30

We move all terms to the left:

(3x)(-2x)-(-30)=0

We add all the numbers together, and all the variables

3x(-2x)+30=0

We multiply parentheses

-6x^2+30=0

a = -6; b = 0; c = +30;
Δ = b2-4ac
Δ = 02-4·(-6)·30
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*-6}=\frac{0-12\sqrt{5}}{-12}
=-\frac{12\sqrt{5}}{-12}
=-\frac{\sqrt{5}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*-6}=\frac{0+12\sqrt{5}}{-12}
=\frac{12\sqrt{5}}{-12}
=\frac{\sqrt{5}}{-1}
$